LanguagesUnderstanding Structs in Go

Understanding Structs in Go

The struct is an aggregate type that is used to group one or more named values and treat it as a single entity. This is particularly useful for creating custom types using one or more built-in types. The values that we typically store in a slice are of the same types, but if we create a struct we can store more than one value of different types and treat it as a single entity. We can also create an array of structs to create a list of custom type entities. The article explains the use of structs in Go with coding examples.

Structs in Go

A struct is an aggregate type where we can group multiple arbitrary types of elements as a single entity. The idea is not very different (unless we use an interface{}) from the struct that we use in C/C++. Each element declared within the struct is called a field. Imagine a database record where we may want to work with an entity such as Book. The Book entity typically consists of fields such as ISBN number, title, edition, publisher, price, category, and so on. Using structs, what we can do is create a single unit such as an entity consisting of multiple fields whose types are different from one another. We can then use this single unit in a variety of ways. For example, we can create an array of this entity and store multiple Book data points or create a single instance of it, among other possibilities.

Here is how we declare a struct Book and create one or more instances of this unit.

type Book struct {
	ISBN 		string
	Title		string
	Edition 	string
	Publisher	string
	Price		float
	Author	string	

Note that fields are typically written one per line. However we can also combine fields of the same type as follows:

type Book struct {
	ISBN, Title, Edition, Publisher, Author string
	Price	float

To create an instance of the struct type Book we may write as follows:

var b1, b2, b3 Book
var b5 Book

We also can create a pointer and assign a struct reference or use a new() function to create a struct reference dynamically and assign the value to a pointer variable, as in this example:

var bkPtrRef *Book
bkPtrRef = &b1

//using new() function
var bkPtr *Book
bkPtr = new(Book)

The individual field in the struct can be accessed using the dot(.) operator:

b1. id = 101

Unlike C/C++ where we may use the (arrow)-> operator or dereference operator(*.) with the pointer, in Go we can simply use the dot(.) operator with a pointer to struct in much the same way we access through a struct instance.

// struct instance
var b1 Book
b1.ISBN = "8170283701"
b1.Title = "Mission to Moon"
b1.Edition = "2015"
b1.Publisher = "ABC Publisher"
b1.Price = 140.00
b1.Author = "donald"

//struct pointer
var ptr *Book = new(Book)
ptr.ISBN = "8170287723"
ptr.Title = "Mission to Mars"
ptr.Edition = "2013"
ptr.Publisher = "ABC Publisher"
ptr.Price = 160.00
ptr.Author = "mickey"

A struct example in Go

Here is a very simple example to show how we can create a singly linked list using structs. It is actually a copy of one of my C code creations and I made a few changes to make it work in Go just to see how simple it is to switch from C to Go.

package main

import (

type Node struct {
	info int
	next *Node

func makeNode(val int) *Node {
	var p *Node
	p = new(Node) = val = nil
	return p

func makeList(root *Node) *Node {
	var num int
	var ptr *Node
	ptr = nil
	for {
		fmt.Print("Enter a value (-999) to stop: ")
		fmt.Scanf("%d", &num)
		if num == -999 {
		if root == nil {
			root = makeNode(num)
			ptr = root
		} else { = makeNode(num)
			ptr =
	return root

func printList(p *Node) {
	for ; p != nil; p = {

func main() {
	var root *Node = nul
	root = makeList(root)


Enter a value (-999) to stop: 11
Enter a value (-999) to stop: 22
Enter a value (-999) to stop: 33
Enter a value (-999) to stop: 44
Enter a value (-999) to stop: 55
Enter a value (-999) to stop: 66
Enter a value (-999) to stop: -999

Slice of structs

We can create a slice of structs. The following example illustrates how the items variable is declared as a slice of struct type. Notice that the struct declared here is unnamed but we can access it via the field name and not use index values as we typically do with a slice. The advantage of using a struct is that we can use different data types for the fields, which simply is not possible with a plain slice.

items := []struct {
	name     string
	quantity int
	price    float64
}{{"PRT34", 5, 5.67}, {"XZE77", 6, 9.67}, {}, {"URT63", 6, 3.35}, {"LKJ98", 4, 4.36}, {"NHT45", 2, 8.25}}

for _, item := range items {
	fmt.Printf("%s\t%d\t%v\n",, item.quantity, item.price)

Note that the number fields as an empty item in the slice of struct is automatically initialized with 0 values.

Embedding a slice within a struct

We have seen how to access named variables within a struct. But what if we want to put a slice inside a struct construct? Let us try an example by creating two structs as follows.

type author struct {
	Firstname string
	Lastname  string
	bio       string
type Book struct {
	ISBN      string
	Title     string
	Edition   string
	Publisher string
	Authors   []author
	Price     float64

authors := []author{{"AA", "BB", "a sample bio of AA"},
		{"CC", "DD", "a sample bio of CC"},
		{"EE", "FF", "a sample bio of EE"}}

b1 := Book{"12345678", "Title1", "2015", "xyz publisher", authors, 140.60}


Observe that the Authors in the Book struct is a slice of the author struct. We first create a slice of author, populate all the fields in the order and then set the Authors field with the created author slice and finally print it (as illustrated in the above code sample).

Comparing structs

One of the common needs for any type is comparability. In Go, struct is also comparable provided the fields declared inside the struct are comparable using the common comparison operator == and !=. Here is an example.

type item struct {
	qty   int
	price float64
	name  string

it1 := item{5, 6.56, "aa"}
it2 := item{6, 5.56, "aa"}
it3 := item{5, 6.56, "aa"}
fmt.Println(it1 == it2) 	//false
fmt.Println(it1 == it3)		//true

What if another struct type is embedded in a struct; does the comparison work? It still works, as in this example.

type qty struct {
	val int

type price struct {
	val float64

type item struct {
	quantity qty
	amount   price
	name     string

var it1 item
it1.quantity.val = 10
it1.amount.val = 4.56 = "AA"

var it2 item
it2.quantity.val = 10
it2.amount.val = 5.56 = "AA"

fmt.Println(it1 == it2) //false

Anonymous fields

In Go we can declare anonymous fields inside a struct. These are no-name fields, but the type of the field must be of a named type or a pointer to a named type. Here is an example.

type item struct {
	name string

it1 := item{qty{10}, price{5.56}, "AA"}

Note that anonymous fields have implicit names. We cannot declare more than one anonymous field, otherwise the implicit name would conflict.


The struct is an important type and has many interesting uses. Here we have skimmed over some of the common ways the struct can be used in Go programming. In general, it enables us to group many arbitrary types into a single entity. This single entity can then be passed to a function, stored in an array and used as a list of entities, copy them as a unit, and so on. It comes in quite handy while creating data structures like linked lists, trees, graphs, and more.

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